Question

(In the given figure, AP.is a radius of
circle ABC and diameter of circle APQ.
Prove that): AQ = QC.
Set-2​

Answer 1

Given : In the given figure, AP.is a radius of  circle ABC and diameter of circle APQ.

To Find : Show that AQ = QC

Solution:

AP is diameter of smaller circle

=> ∠AQP = 90°

=> ∠CQP = 90°   as AQC is a straight line

CP = AP = Radius of larger circle

AQ² = AP² - PQ²

CQ² = CP² - PQ²

CP = AP

Hence AQ² =  CQ²

=> AQ = CQ

QED

Hence proved

Learn More:

ab is a diameter of the circle such that angle A is equal to 35 degree ...

https://brainly.in/question/12240695

75. The measure of an inscribed angle of circle is 65°, then what will ...

https://brainly.in/question/15393659