(In the given figure, AP.is a radius of
circle ABC and diameter of circle APQ.
Prove that): AQ = QC.
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Given : In the given figure, AP.is a radius of circle ABC and diameter of circle APQ.
To Find : Show that AQ = QC
Solution:
AP is diameter of smaller circle
=> ∠AQP = 90°
=> ∠CQP = 90° as AQC is a straight line
CP = AP = Radius of larger circle
AQ² = AP² - PQ²
CQ² = CP² - PQ²
CP = AP
Hence AQ² = CQ²
=> AQ = CQ
QED
Hence proved
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