In the given figure, AP is perpendicular to QR. PR is greater than PQ and PQ=PS. show that AR is greater than AQ.
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Step-by-step explanation:
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Step-by-step explanation:
In ∆APQ and ∆APS,we have:
PQ=PS(given)
AP=AP(common)
APQ=APS(90°)
∆APQ is congruent to ∆APS
But, int. angle ARS < ext. angle ASQ
So, AQ<AR(C.p.c.t)
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