Question

In the given figure AP is tangent to the circle with centre O . OA =16 and AP=30 QP=x ..find x

Solve using Pythagoras theorem directly please

Answer 1

$here \: is \: your \: answer \: mate$

${op}^{2} = {ap}^{2} + {ao}^{2} \\ {x}^{2} = {16}^{2} + {30}^{2} \\ {x}^{2} = 256 \: + \: 900 \\ {x}^{2} = 1156 \\ x = 34$

$mark \: \: as \: brainlist$

Answer 2

Answer:

Step-by-step explanation:

where is fig.