In the given figure ,AP perpendicular to BC,DQ perpendicular to BC BAC similar to BDC then prove A ABC ~ADBC.
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Given:
AP ⊥ BC —————————— 1
DQ ⊥ BC —————————— 2
️ BAC ~ ️ BDC ———————— 3
To prove: ️ ABC ~ ️ DBC
Proof:
From equation 3, we have
∠ ABC = ∠ DBC
∠ BAC = ∠ BDC
∠ ACB = ∠ DCB
From the above equations, ️ ABC ~ ️ DBC (AAA similarity)
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