Question

In the given figure, APQR and ASQR are isosceles. Find the value of x​

Answer 1

Answer:

X = 25°

Step-by-step explanation:

Base angles of an isoceles triangle are equal. Angle SQR = Angle SRQ.

Sum of angles of triange = 180°.

Therefore, Angle RSQ + SRQ + SQR = 180°

=> 70° + 2*Angle SQR = 180°

=> Angle SQR = (180-120)/2 = 30

In isosceles triangle, base angles

Angle PQR = Angle PRQ,

sum of angles of triange = 180°,

=> Angel PQR + PRQ + RPQ = 180°

=> Angel PQR = 55°

X = Angle PQR – Angle SQR

= 55 - 30

= 25°

Answer 2

Answer:

x= 55°

Step-by-step explanation:

as triangle pqr is isosceles so,

PQ=PR

angle PQR = angle PRQ = x --------------- (angles opposite to the equal sides of a triangle are equal)

Now,

=> angle PQR + angle PRQ + angle QRP = 180° ------(angle sum property of a triangle)

=> x + x +70° = 180°

=> 2x = 180° - 70°

=> 2x = 110°

=> x = 110°\2

=> x = 55°