Question

In the given figure ar (△XYZ) = 118 m2 and XS = 4m. If XS⊥YZ, then YZ​

Answer 1

Answer:

YZ = 59 m

Step-by-step explanation:

Area to ΔXYZ = 118 $m^2$ (Given )

and XS⊥YZ

XS = 4 m

Area of triangles  = $\frac{1}{2}$ base x height

so in ΔXYZ

118 = (1/2) ( YZ ) *(XS)

118 = (1/2) ( YZ ) *(4)

YZ = 118/2 = 59 m

YZ =59 m

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Answer 2

Answer:

The measure of side YZ is 59m.

Step-by-step explanation:

Given:

A(ΔXYZ) = 118 m²

XS = 4m

XS ⊥ YZ

To find:

YZ = ?

Solution:

We know that area of a triangle is given as half the product of its base and height.

In the given ΔXYZ, XS is the height and YZ is the base. Therefore,

A(ΔXYZ) = (1/2)×XS×YZ

Substituting the given values, we get

118 = (1/2) × 4 × YZ

118 = 2×YZ

YZ = 118/2

YZ = 59m

Therefore, the length of side YZ is 59m.

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