Question

in the given figure AS||BT;<4=<5 SB bisects <AST.find the measure of <1​

ANSWER:
is given in above picture

Answer 1

ANSWER

AS∥BT [ Given ]

∴ ∠2=∠5 [ Alternate angles are equal ]

⇒ ∠2=∠3

⇒ Let, ∠2=∠3=∠5=x

⇒ In △BST, ∠RSB is an exterior angle.

∴ ∠RSB=∠SBT+∠BTS [ By exterior angle property ]

∴ ∠1+∠2=∠5+∠4

∴ ∠1+x=x+x

∴ ∠1+x=2x

∴ ∠1=x

⇒ ∠1+∠2+∠3=180

o

[ Since, ∠1,∠2 and ∠3 forms a linear pair ]

⇒ x+x+x=180

o

⇒ 3x=180

o

∴ x=

3

180

o

=60

o

∴ Measure of ∠1 is 60

o

.

Answer 2

Step-by-step explanation:

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