Question

in the given figure aside find the values of x and y

Answer 1

Answer:

Let,

LA = x+10

LB = 2x+4

LC = 5y-5

LD = 2y-4

ABCD is a cyclic Quadrilateral

LA + LC = 180°

x + 10 + 5y - 5 = 180°

x + 5y + 5 = 180°

x + 5y = 175° --eq(1)

LB + LD = 180°

2x + 4 + 2y - 4 = 180°

2x + 2y = 180°

x + y = 90° --eq(2)

By elimination method

$x + 5y = 175 \\ x + \: \: y \: \: \: = 90 \\ - \: \: \: - \: \: \: \: \: \: \: \: \: -$

___________________________

$4y = 85 \\ y = \frac{85}{4}$

By eq(2)

$x + \frac{85}{4} = 90 \\ x = 90 - \frac{85}{4} \\ x = \frac{360 - 85}{4} \\ x = \frac{275}{4}$

HOPE THIS ANSWER WILL HELP YOU..........

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# jasleenlehri13.......☺✌

Answer 2

Answer:

2x+4+2y-4=180

x+y=90............(1)

x+10+5y-5=180

x+5y+5=180

x+5y=175...........(2)

1-2

4y=85

y=85/4. =21.25

x=68.75

hope it helps.....