in the given figure at right, find angles acd and angle aed
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Answered by
21
Step-by-step explanation:
In triangle ABC,
15+40+angle ACB = 180°( angle sum property)
angle ACB= 180 - 55
angle ACB = 125°
angle ACB + angle ACD = 180° ( linear pair)
angle ACD=180- 125
angle ACD =55
angleEDC + angle ACD = angle AED( external angle property)
52+55=angle AED
107°= angle AED
Therefore, angle ACD= 55° and angle AED= 107°
Answered by
7
Answer:
acd=40+15=55
180-55=125(the angle sum property of a triangle is 180 degrees)
c=55
aed=73
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