in the given figure ay is perpendicular to zy and by is perpendicular to xy such that ay=zy and by=xy. prove that ab=zx
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Answer:
Given AY = ZY ; AY⊥ZY
and BY = XY;BY⊥XY
To prove AB = ZX
Proof ∵BY⊥ XY and AY ⊥ ZY
∴∠BYX = 90°
and ∠AYZ = 90°
=>∴BYX =∴AYZ
On adding∠AYX both sides, we get
∠BYX+ ∠AYX =∠AYZ + ∠AYX
=> ∠AYB = ∠ZYX
Now, in ∆AYB and ∆ZYX, we have
AY = ZY
BY = XY
and ∠AYB = ∠ZYX [proved above]
image
[by SAS congruence rule]
AB = ZX
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