In the given figure ∠B=90
, AB=6cm, BC=8cm and AC=10cm then the value of
Sin(90-θ) is
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6
Two answers with respect to two figures, since the figure was not provided in the question.
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Step-by-step explanation:if sin(90-0)=cos o
- cos o =adjacent / hypotenuse
- so here adjacent = 8
- and hypotenuse = 10
so our answer will be 8/10
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