Question

In the given figure ∠ B <∠A and ∠ C <∠ D. Show that AD < BC​

Answer 1

Answer:

To prove: AD < BC

We can use the fact that in any triangle, the side opposite to the larger (greater) angle is longe

Step-by-step explanation:

In ΔAOB, ∠B < ∠A (given)

AO < OB (The side opposite to the smaller angle is smaller)   ... (1)

In ΔCOD, ∠C < ∠D

OD < OC (The side opposite to the smaller angle is smaller)  ... (2)

On adding Equations (1) and (2), we obtain

AO + OD < BO + OC

AD < BC

Hence, proved