Question

In the given figure, BA ǁ ED and BC ǁ EF. Show that ∠ABC + ∠DEF = 180⁰ pls explain with proper steps ​

Answer 1

Answer:

produce ED to meet BC at p

AB || PE and BPC is the transversal

angle ABP + angleBPE=180°

angle ABC + angle BPE=180°...(1)

Now , EF||BPC and EP is the tranversal

angleBPE=anglePEF=angleDEF....(2)

we can also write anglePEF as angle DEF

HENCE ANGLE ABC+ANGLE DEF = 180° [using (2) ]

Step-by-step explanation:

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