Question

In the given figure, BAC = 40°, ACB = 90° and BED = 100°, Then BDE =?​

Answer 1

Answer:

∠BDE = 30°

Step-by-step explanation:

Let's take triangle ACB

By angle sum property,

∠ACB + ∠CBA + ∠BAC = 180

90°  +  ∠B + 40° = 180°

∠B = 180° - 130° = 50°

Now in triangle BED,

By angle sum property,

∠BED + ∠EBD + ∠BDE = 180°

100° +  50° + ∠BDE = 180°

∠BDE = 180° - 150° = 30°

Answer 2

Answer:

Answer:

LBDE=30° (L is symbol of angle)

Step-by-step explanation:

First, lets find LABC (L is symbol of angle)

LABC + LACB + LBAC=180° (angle sum property)

LABC + 90°+ 40° = 180°

LABC=180-130

LABC=50°=LEBD

Now, lets find LBDE

LBDE + LBED + LEBD=180° (Angle Sum Property)

LBDE + 100° + 50°=180°

LBDE= 180-150

LBDE=30°