Question

In the given figure BC = 4cm, CD = 3cm.CE = 2cm and AC = 6cm .If AB = 3.2 cm then find DE.​

Answer 1

Answer:

WE NEED USE 'THE S.A.S SIMILARITY RULE' TO FIND THE LENGTH OF THE REQUIRED SIDE!

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Answer 2

The length of DE is $1.6 \ cm$

Explanation:

It is given that $\mathrm{BC}=4 \mathrm{cm}$, $CD=3cm$ , $\mathrm{CE}=2 \mathrm{cm}$ and $A C=6 \mathrm{cm}$

If $AB=3.2cm$, we need to find DE

Since, the values of the two triangles $\triangle A B C \sim \triangle C D E$ are proportional, let us solve using the SSS property.

Thus, we have,

$\frac{A C}{C D}=\frac{B C}{C E}=\frac{A B}{D E}$

Hence, to find DE, we have,

$\frac{A C}{C D}=\frac{A B}{D E}$

Now, substituting the values, we have,

$\frac{6}{3}=\frac{3.2}{D E}$

Cross multiplying, we have,

${6}{D E}={3.2}(3)$

Dividing by 6 on both sides, we have,

${D E}=\frac{{3.2}(3)}{6}$

Simplifying, we have,

$DE=\frac{9.6}{6}$

$DE=1.6 \ c m$

Thus, the value of DE is $1.6 \ cm$

Learn more:

(1) brainly.in/question/12613949

(2) brainly.in/question/1735891