In the given figure, BC = AD and AC = BD. The length of AB, BC, and
OD are 6 cm, 9 cm, and 7 cm respectively. What is the perimeter of
ΔAOB?
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Answer:
20 cm
Step-by-step explanation:
let ABCD be the figure where AC=BD AND AD=BC
IF AC=BD THEN OD=OB=OC=OA (IF O IS THE POINT OF INTERSECTION PF AC AND BD)
ALSO AD = BC = 9 CM
OD=OA=OB= 7 CM
ALSO AB=6 CM
THEREFORE IN ️AOB THE SIDES ARE AB,OA,OB
THEREFORE PERIMETER = AB +OA+OB =6+7+7 CM = 20 CM
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