Question

In the given figure BC = CA and angle A = 40 degrees. What is the measure of angle ACD?

Answer 1

Answer:

Angle ACD = 80°

Step-by-step explanation:

Since triangle ABC is an isosceles trangle

A=B = 40° (Base angle are equal)

A+B+C=180° (Interior angles of a triangle measure 180°)

40°+40°+ C = 180°

C=180°-80°

C = 100°

100°+C=180 °(straight line angle)

C=180°-100°

C=80°