Question

in the given figure bc||de and o is the centre of the circle.if ang.cad=x°; find the value of ang.bac​

Answer 1

∠ADC= 21 ∠AOC

(Angle subtended by a chord on mayor area is half of that subtended on center)

∴∠ADC= 21 ×130=65 ∘Now, ADCB is cyclic quadrilateral ⇒ Sum of opposite Angles is 180 ∘

∴∠ABC+∠ADC=180 ∘∠ABC+65=180 ∘

∠ABC=115 ∘