In the given figure BC is a chord and CD is a tangent through the point C. If angle AOC = 118° then find the angle ACD.
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Answer:
= ∠ACD = 59°
Step-by-step explanation:
= AO = CO
= ∠OAC = ∠OCA
= 2∠OCA= 180°-118°
= 2∠OCA= 62°
= ∠OCA= 62°÷2 = 31°
= ∠OCD = 90° (Tangent to a circle)
= ∠ACD = 90°-31° = 59°
Hope it helped...
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