Question

in the given figure BC is daimeter if AB =3cm AC=4cm and angle 90° .Find the area of the shaded region (₹3.14)

Answer 1

Answer:

Step-by-step explanation:

in triangle abc <a=90deg

using pythagorus theorem bc^2=ac^2 +ab^2

bc^2= 3^2+4^2

       =9+16=25

bc=5cm

since bc is diameter =5

radius=5/2

area of shaded region =area of semicircle - area of triangle

                                      = 1/2 pie r^2 - 1/2 *b*h

                                      = 1/2 *3.14 *5/2*5/2- 1/2*4*3

                                      = 1.57*25/2 - 6

                                      = 38.32/4 - 6

                                      =  9.56 - 6

                                      = 3.56 cm^2

Answer 2

Answer:

In triangle abc <a=90°

using pythagorus theorem bc^2=ac^2 +ab^2

bc^2= 3^2+4^2

       =9+16=25

bc=5cm

since bc is diameter =5

radius=5/2

area of shaded region =area of semicircle - area of triangle

= 1/2 πr^2 - 1/2 πr^2      

= 1/2 *3.14 *5/2*5/2- 1/2*4*3

= 1.57*25/2 - 6

 = 38.32/4 - 6  

=  9.56-6

= 3.56 cm^2..............answer