in the given figure BC PARALLEL DE if angle ACE IS EQUAL TO ANGLE CDE =90 degree and angle ACB =30 degree the n the measure of DCE
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DCE=∠EAB (Alternate angles as AB∣∣DE and AE is transversal)
∠DEC=35
∘
In △DCE, we have
∠DCE+∠CED+∠CED=180
∘
(Angle sum property)
∠DCE+35
∘
+53
∘
=180
∘
∠DCE=180
∘
−88
∘
=92
∘
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