Math, asked by smv96, 11 months ago

in the given figure BC passes through the centre of a circle. A B and C are concyclic and Angle B is 44 degree more than angle C the values of X and Y respectively are​

Attachments:

Answers

Answered by gkmass100
7

Answer:

3

Step-by-step explanation:

hope it helps u...........

Answered by Anonymous
6

The values of x and y are 5 and 2, respectively.

Given:

Angle B is 44° more than angle C

To find:

The values of x and y

Solution:

We can obtain the required values by forming an equation.

The value of angle B=(10x+17)°

The value of angle C=(15y-7)°

Now, we know that angle B is 44° more than angle C.

So, angle B=angle C+44°

10x+17=15y-7+44

10x-15y=44-7-17

10x-15y=20

2x-3y=4 (1)

We know that angle A=90° since it is an angle formed in the semi-circle.

Angle A+angle B+Angle C=180°

Using values,

90°+10x+17°+15y-7°=180°

10x+15y=180°-100°

10x+15y=80°

2x+3y=16° (2)

On adding (1) and (2), we get

2x-3y+2x+3y=4+16

4x=20

x=5

We will put x=5 in (1),

2x-3y=4

2(5)-3y=4

10-4=3y

6=3y

2=y

Therefore, the values of x and y are 5 and 2, respectively.

#SPJ3

Similar questions