Question

. In the given figure BD and CE are the altitudes of triangle ABC such that BD = CE a) Provethat
ΔCBD ΔBCE
b) Is angle DCB = angle EBC
c) Give reasons

Answer 1

$\huge\underbrace\mathtt\color {pink}Answer$

Given,

BD and CE are altitude of triangle ABC

To prove,

∆CBD=∆BCE

Is angle DCB=Angle EBC

Reason.

Proof,

In ∆ABD&∆ACE

ADB=ACE

BAD=CAE

BD=CE

∆ABD≈∆ACE

AB=AC