Question

in the given figure, Bd||CE

AC=BC, angle ABD= 20° and angle ECF=70° find angle GAC.
hint. angle DBC= angle ECF=70°​

Answer 1

Answer:

∠GAC = 130°

Step-by-step explanation:

AC = BC (given)

ΔABC is an isosceles triangle (2 sides equal)

∠DBA = 20° (given)

∠DBC = ∠ECF = 70° (given)

∠ABC = 70-20 = 50°

∠CAB = ∠ABC = 50° (isosceles triangle)

∠GAC = 180-∠ABC (linear pair)

∠GAC = 180-50

∠GAC = 130°

Answer 2

Answer:

hi hope this helps uu

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answer

thanku!