Question

In the given figure BD is a diameter of center 0 , angle COD = 92 degree and angle ABD 65 degree. Then y equal?

Answer 1

Answer:

21 Degrees

Step-by-step explanation:

Explanation attached.

Answer 2

y = 21° if BD is a diameter of center O , angle COD = 92 degree and angle ABD 65 degree  

Step-by-step explanation:

 in ΔOCD

 OC = OD = Radius

∠OCD = ∠ODC

∠COD = 92°

Sum of angles of triangle = 180°

∠OCD +∠ODC + ∠COD = 180°

=> 2∠OCD + 92° = 180°

=> 2∠OCD  = 88°

=> ∠OCD = 44°  

∠DCA = ∠DBA  ( Angle by same chord AD in same arc segment)

=> ∠DCA =   65°

∠DCA = ∠ACO + ∠OCD

=>  65° = y + 44°

=>  y = 21°

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