In the given figure, BE and CE are the bisectors of the angles B and C respectively of △ABC. If EF⟂BC and
CD⟂AB, then prove that
(i) △BED=△BEF
(ii) AE bisects ∠A
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Answered by
9
Answer:
1) by AA congruence
Step-by-step explanation:
given,
in ∆BED and ∆ BFE
angle B is common
angle B= angle B(common)
angle D=angle F(90° each)
so by AA congruence both are equal
2) expand line FE up to angle A
EF is perpendicular to BC so the angle form at the top is angle A
and AE bisects angleA
Answered by
3
Answer:
second one should be an isoscsles, then you have to prove how BF eqauls FC.
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