In the given figure, BE and CF are two equal altitudes of L ABC. Show that
(1) ABE congruent to ACF
(1) AB = AC
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(i) Based on the △ ABE and △ ACF
We know that ∠ AEB = ∠ AFC = 90°
It is given that BE = CF
From the figure we know that ∠ A is common for both ∠ BAE and ∠ CAF
So we get ∠ BAE = ∠ CAF = ∠ A
Therefore, by ASA congruence criterion we get △ ABE ≅ △ ACF
(ii) As we know that △ ABE ≅ △ ACF
It is proved that AB = AC.
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