Question

In the given figure below, AB||CD||EF and angle ABC=60°,angle CEF = 140°Find the value of angle BCE​

Answer 1

Answer:

value of x is 20°.

Step-by-step explanation:

we have,

AB || CD

Angle ABC = Angle BCD ( alternate angles )

60° = Angle BCD

Angle BCD = 60°

also,

EF || CD

Angle FEC + Angle ECD = 180°

( as co - interior angles of parallel lines )

140° + Angle ECD = 180°

Angle ECD = 180° - 140° = 40°

Angle ECD = 40°

angle BCD = 60°

Angle BCE + Angle BCD = 60°

x + 40° = 60°

x = 60° - 40°

x = 20° ans.

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Answer 2

Answer

x=20°

Step-by-step explanation:

we have,

ABIICD

Angle ABC=angle BCD(alternate angles)

60°=Angle BCD

Angle BCD=60°

also

EFIICD

angle FEC +Angle ECD=180°(As Co. interior angles of parallel lines)

140°+angle ECD=180°

angle BCD=60°

angle BCE+Angle BCD=60°

x+40•=60°x=60°–40°

x=20°