In the given figure below, l1 ∥l2, and mis atransversal, find the values of x,y and z.
Answers
☆Heya! mate figure is not given in question please ask with attachments next tome
Answer:
−
6
1
×
7
4
+
2
1
−
7
3
×
6
1
RULES :
Move Left ➝ Right & carry out Division/Multiplication, which comes fast.
Move Left ➝ Right & carry out Addition/Subtraction, which comes fast.
PROPERTY :
✯ Here we use B O D M A S property.
B ➝ Bracket
O ➝ Of [power, percent, fraction]
D ➝ Division
M ➝ Multiplication
A ➝ Addition
S ➝ Subtraction
SOLUTION :
\begin{gathered}:\implies\:\:\tt{\bigg(-\dfrac{1}{6}\times{\dfrac{4}{7}}\bigg)\:+\:\dfrac{1}{2}\:-\:\bigg(\dfrac{3}{7}\times{\dfrac{1}{6}}\bigg)\:} \\ \end{gathered}
:⟹(−
6
1
×
7
4
)+
2
1
−(
7
3
×
6
1
)
\begin{gathered}:\implies\:\:\tt{-\:\dfrac{4}{42}\:+\:\dfrac{1}{2}\:-\:\dfrac{3}{42}\:} \\ \end{gathered}
:⟹−
42
4
+
2
1
−
42
3
\begin{gathered}:\implies\:\:\tt{\dfrac{1}{2}\:+\:\bigg(-\:\dfrac{4}{42}\:-\:\dfrac{3}{42}\bigg)\:} \\ \end{gathered}
:⟹
2
1
+(−
42
4
−
42
3
)
\begin{gathered}:\implies\:\:\tt{\dfrac{1}{2}\:-\:\dfrac{7}{42}\:} \\ \end{gathered}
:⟹
2
1
−
42
7
\begin{gathered}:\implies\:\:\tt{\dfrac{21\:-\:7}{42}\:} \\ \end{gathered}
:⟹
42
21−7
\begin{gathered}:\implies\:\:\tt{\dfrac{14}{42}\:} \\ \end{gathered}
:⟹
42
14
\begin{gathered}:\implies\:\:{\bf{\pink{\dfrac{1}{3}\:}}}~~~~~(Answer) \\ \end{gathered}
:⟹
3
1
(Answer)