Question

In the given figure, BL perpendicular to AC, MC perpendicular to LN,AL = CN, BL = CM. Proove that triangle ABC cogruent to triangle NML​

Answer 1

Step-by-step explanation:

Hope this will help.....

Answer 2

ΔABL ≈ ΔNML

GIVEN

BL ⏊ AC

MC⏊LN

AL = CN

BL = CM

u

TO FIND

To prove ΔABC is congruent to ΔNML

SOLUTION

We can simply solve the above problem as follows -

In ΔABL and ΔMNC

It is given that,

AL = CN

BL = CM

∠BLA = ∠MCN = 90°

By S-A-S criterion

ΔABL ≈ ΔMNC

Therefore, By CPCT;

AB = MN (equation 1)

∠BAL = ∠MNC (equation 2)

It is given,

AL = CN

So,

AL+LC = CN+AL

Therefore,

AC = LN

In ΔABL and ΔMNC

AC = LN (proved)

∠BAL = ∠MNC

AB = MN (proved)

Therefore, By side- angle-side criterion

ΔABL ≈ ΔNML

Hence, Proved.

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