Question

In the given figure, BO and CO are the bisectors of ABC
and ACB respectively. If BAC = 60°, prove that BOC=120
​

Answer 1

Answer:

AB=BC

So

ABC=60°

BCA=60°

So ABC is an equilateral triangle

BCO=60/2=30°

CBO=60/2=30°

BCO+CBO+BOC=180°

30°+30°+BOC=180°

60°+BOC=180°

BOC=180°-60°

BOC=120°

Answer 2

Answer:

Answer:

Step-by-step explanation:

Given that, BAC=60°.

We see that,

BAC=BCA=ABC=60°

⇨OBC=OCB=1/2ABC=1/2BCA=30°

Now, BOC+BCO+CBO=180°

⇨BOC+30°+30°=180°

⇨BOC = 180° - 60°

.•.BOC = 120° (Proved)

It may help you.