In the given figure , BO and CO are the bisectors of the exterior angles meeting each other at O . If angle A = 70⁰ find angle BOC .
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answer is 55°
Step-by-step explanation:
sum of angles on a straightline=180∘
=>∠ABC=180 ∘ −2θ
and∠ACB=180 ∘ −2α
In△ABC
=>∠A+∠ABC+∠ACB=180 ∘
=>70 ∘ +180−2θ+180−2α=180
=>250 ∘ −(2θ+2α)=0
=>2(θ+α)=250 ∘
=>θ+α=125 ∘ −(1)
In△BOC
=>∠CBO+∠BCO+∠BOC=180 ∘
=>θ+α+∠BOC=180 ∘
=>125 ∘ +∠BOC=180 ° −from(1)
∴∠BOC=55 ∘
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