Question

In the given figure, BOC is a diameter of a circle with centre O. if a b and CD are two chords such that AB parallel to CD and AB = 10cm then find CD​

Answer 1

Answer:

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Step-by-step explanation:

Construct OL⊥AB and OM⊥CD

Consider △OLB and △OMC

We know that ∠OLB and ∠OMC are perpendicular bisector

∠OLB=∠OMC=90

o

We know that AB∥CD and BC is a transversal

From the figure we know that ∠OBL and ∠OCD are alternate interior angles

∠OBL=∠OCD

So we get OB=OC which is the radii

By AAS congruence criterion

△OLB≅△OMC

OL=CM (c.p.c.t.)

We know that the chords equidistant from the centre are equal so we get

AB=CD

Therefore, it is proved that AB=CD

Answer 2

Answer:

correct answer is 10 CM...