Question

In the given figure, C is a point on AB such that 3AC = 2BC . Taking AC and BC as one of the sides, equilateral triangles are formed. The ratio of ar(∆ ADC to ar * (∆*C * E * B) is ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

4 : 9

Step-by-step explanation:

These two triangles are similar by AAA rule. (AAA Similarity rule)

And for similar triangles, the area is found by Area of Similar Triangles Theorem

Area of similar triangle theorem helps in establishing the relationship between the areas of two similar triangles. It states that "The ratio of the areas of two similar triangles is equal to the square of the ratio of any pair of their corresponding sides".

So ar(∆ ADC) : ar(∆ CEB) = (AC/BC)^2

=(2BC÷3/BC)^2

=(2/3)^2

=4:9