Question

In the given figure C is the mid point of BD and AB=AD Prove that ∆ABC=ACD
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Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

In ∆ ABC and ∆ACD

AB = AD ( given)

AC = AC (common)

BC = CD (c is the mid point)

so,

∆ABC is congruent to ∆ACD (by SSS)

hope it will help you.