Question

In the given figure CA and CB are the tow tangens to a circle with center 0, so that angle AOB=60 degree, then the value of angle ACB Is​

Answer 1

Answer:

120

Step-by-step explanation:

LOAC=90DEG

LOBC=90DEG

And

LAOB=60DEG

Then, we know, means you know that sum of angles of quadrilateral is 360deg

So,answer is 360-(180+60)=360-240=120..

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Answer 2

Step-by-step explanation:

In the figure given below f CA and CB atle two tangents to a circle with centre 0 so that /_AOB=60^(@). then find /_ACB.