Question

in the given figure CAB = 25 degree find angle BDC,DBA,COB​

Answer 1

∠BDC =  25° , ∠DBA = 65° & ∠COB =  50° if in given fig ∠CAB = 25°

Step-by-step explanation:

∠CAB = 25° ( Given)

∠BDC = ∠CAB  as both the angles are subtended by Chord BC

=> ∠BDC =  25°

in ΔDBP

∠DBP + ∠BDP + ∠BPD = 180°

∠DBP = ∠DBA

∠BDP = ∠BDC =  25°

∠BPD = 90°

=> ∠DBA + 25° + 90° = 180°

=> ∠DBA = 65°

∠COB = 2∠CAB  = 2 ∠BDC  ( angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.)

=> ∠COB =  2 * 25°

=> ∠COB =  50°

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