Question

In the given figure, CAB = 40°, AC = AB and BC = BD. Find :
(i) ACB. (ii) CDB ​

Answer 1

Answer:

Join / Login

Class 10>>Maths>>Triangles>>Criteria for Triangle Similarity>>In given figure, CAB = 90^0 and AD BC

Question

In given figure, ∠CAB=900 and AD⊥BC. If AC=75 cm. AB=1 m and BD=1.25 m, find AD

Medium

Open in App

Solution

Verified by Toppr

We have,

         AB=1 m=100 cm, AC=75 cm and BD=125 cm.

In △BAC and △BDA, we have

        ∠BAC=∠BDA         [Each equal to 90∘]

and,  ∠B =∠B

So, by AA-criterion of similarity, we have

      △BAC∼△BDA

⇒   BDBA=ADAC

⇒  125100=AD75

⇒  AD=100125×75cm=93.75cm

Answer 2

Answer:

angle CBA =angle ACB

So,

40+angle CBA +angle ACB=180

( Angle sum property)

let angle CBA and angle ACB

40+x+x=180

x=180-40/2

70

angle CBA =70

angle ACB=70;

angle BCD=angleBDC

angle CBA+angleCBD=180

180-70=angle CBD

=110

let angle BCDand angleBDC be x

x+x+angleCBD=180

2x=180-angleCBD

x=180-110/2

=35

angleCDB =35

MARK AS BRAINLIEST PLEASE

THANK YOU