In the given figure, CB is parallel to AE find x if angle ADC=92 and angle BCF=20
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In cyclic quad ABCD
Af is parallel tonCB and DA is produced to E such that angle ADC = 92° and FAE = 20°
Now we need to find the measure of angle BCD
In the cyclic quad ABCD,
B+D = 180°
B+92°=180
B= 180°- 92°
B = 88°
Since AF parallel to CB, angle FAB = B = 88°
But angle FAE =20° [GIVEN]
EXT. ANGLE BAE =ANGLE BAF +ANGLE FAE
=88°+22°=108°
But Ext. Angle BAE = Angle BCD
THEREFORE :- ANGLE BCD = 108°
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