In the given figure, CB || QR and. CA || PR. If AQ = 12 cm, , AR = 20 cm, PB = CQ = 15 cm, calculate PC and BR.
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Step-by-step explanation:
Given In the given figure, CB || QR and. CA || PR. If AQ = 12 cm, , AR = 20 cm, PB = CQ = 15 cm, calculate PC and BR.
- From triangle PQR given CB is parallel to QR then
- From basic proportionality theorem
- PC / CQ = PB / BR
- PC / 15 = 15 / BR ----------1
- In triangle PQR, given CA is parallel to PR,
- From basic proportionality theorem
- PC / CQ = AR / AQ
- PC / 15 = 20 / 12
- So PC = 20 x 15 / 12
- So PC = 25 cm
- Now from equation 1 we get
- PC / 15 = 15 / BR
- Or 25 / 15 = 15 / BR
- BR = 15 x 15 / 25
- Or BR = 9 cm
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Given In the given figure, CB || QR and. CA || PR. If AQ = 12 cm, , AR = 20 cm, PB = CQ = 15 cm, calculate PC and BR.
From triangle PQR given CB is parallel to QR then
From basic proportionality theorem
PC / CQ = PB / BR
PC / 15 = 15 / BR ----------1
In triangle PQR, given CA is parallel to PR,
From basic proportionality theorem
PC / CQ = AR / AQ
PC / 15 = 20 / 12
So PC = 20 x 15 / 12
So PC = 25 cm
Now from equation 1 we get
PC / 15 = 15 / BR
Or 25 / 15 = 15 / BR
BR = 15 x 15 / 25
Or BR=9cm
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