Question

In the given figure CD⊥AB, AD = 3 cm, CD = 4cm, BC = 12 cm. Find the value of:
i) sec A ii) tan2B − sec2B iii) cosec2A − cot2A

Answer 1

Answer:

Consider △ACB and △CEF

Both triangles are similar

∴

EF

AB

​

=

3

x

​

⇒

4.5

7.5

​

=

3

x

​

x=

4.5

7.5

​

×3

∴x=5cm

Consider △BCD and △BFE

y

x

​

=

4.5

x+3

​

y

5

​

=

4.5

5+3

​

⇒y=

8

5×4.5

​

∴y=

16

45

​

cm

Step-by-step explanation:

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