Question

In the given figure CD is a diameter which meets chord AB at E such that AE = BE = 8cm. If CE is 4cm find the radius of the circle ​

Answer 1

Answer:

Given that : - CD is diameter which meets chord AB in E . AE = BE = 4 cm , CE = 3 cm.

To find : - Radius of the circle.

Let the radius be R.

Then,

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Mark a point O a the mid point of the circle and join OB. OB = OC = R .

So , OE = ( R - 3).

Then, by Pythagoras theorem,

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(R - 3)² + (4)² = (R)²

=> R² - 6R + 9 + 16 = R²

=> R² - R² - 6R = - 25

=> 6R = 25

=> R = 25/6

=> R = 4.16 cm