In the given figure CE is a tangent to the circle at point C. ABCD is a cyclic quadrilateral. If ∠ABC = 93o and ∠DCE = 35o. Find: (i) ∠ADC (ii) ∠CAD (ii) ∠ACD
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opp angles of a cyclic quad. sum upto 180 so,
angleA + angleC= 180
angleA +35=180
angleA=180-35=145
similarly
angleB+angleD=180
93+angleD=180
angleD=180-93=87
so, angleA=145 and angleD=87
I hope my answer helps you
angleA + angleC= 180
angleA +35=180
angleA=180-35=145
similarly
angleB+angleD=180
93+angleD=180
angleD=180-93=87
so, angleA=145 and angleD=87
I hope my answer helps you
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