In the given figure, chords AB = AC = 6cm. The length of BC, if radius is 5 cm, is
(A) 9.6 cm
(B) 4.8 cm
(C) 19.2 cm
(D) 8.0 cm
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Answer:
your answer is 9.6
Step-by-step explanation:
let od be x and oa be (5-x)
and then use Pythagoras theorem
in triangle ocd
5²=x²+cd²
cd²=25-x²....... 1
in triangle acd
6²=(5-x) ²+cd²
cd²=11+10x-x²....... 2
by eq 1 and 2
11+10x-x²=25-x²
10x=14
x=1.4
cd²=25-(1.4) ²
cd²=23.04
cd=4.8
since bc =2cd
4.8×2
9.6
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