Question

in the given figure,chords AD and BC in the circle,are extended to E and F respectively angle CDE=85,angle DCF=94 then value of angle ABF+angle EAB
​

Answer 1

Answer:

Raj Vishwakarma Can I read Raj Vishwakarma Can I read Raj Vishwakarma Can I read Raj Vishwakarma Can I read Raj

Answer 2

Answer:



∠CDE = 85°; ∠DCF = 94°

Concept used:

Sum of two angles forming a linear pair is 180°.

Sum of opposite angle of cyclic quadrilateral is 180°.

Calculations:

∠CDE + ∠ADC = 180°      (∵ Sum of two angles forming a linear pair is 180°.)

⇒ 85° + ∠ADC = 180°

⇒ ∠ADC = 95°

Now,

∠ABC + ∠ADC = 180°      (∵ Sum of opposite angle of cyclic quadrilateral is 180°.)

⇒ ∠ABC + 95° = 180°

⇒ ∠ABC = 85°

⇒ ∠ABF = 85°      ----(1)

Similarly,

⇒ ∠EAB = 94°      ----(2) 

From (1) and (2),

⇒ ∠ABF + ∠EAB = 179°

∴ The value of ∠ABF + ∠EAB is 179°.