in the given figure d and e are midpoints of AC and BC respectively find angle BAC and a b if de is equal to 1.7 CM
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Given: D and E are mid points of AB and BC respectively. DF∥BC
Since, DF∥BC D is mid point of AB.
By converse of mid point theorem, F is mid point of AC.
Now, E and F are mid points of BC and AC respectively.Thus, by mid point theorem,
EF∥AB or EF∥DB
Since, opposite sides are parallel to each other. Hence, DBEF is a parallelogram.
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