Question

In the given figure, D, E and F are respectively mid points of the sides BC, CA and AB of AABC and P is a point on BC such that APL BC. If ZDEF = 50, then
FPD =​

Answer 1

Step-by-step explanation:

Since line segment joining the mid-points of two sides of a triangle is half of the third side. Therefore, D and E are mid-points of BC and AC respectively.

⇒ DE = 1 / 2 AB --- (i)

E and F are the mid - points of AC and AB respectively .

∴ EF = 1 / 2 BC  --- (ii)

F and  D are the mid - points of AB and BC respectively .

∴ FD = 1 / 2 AC --- (iii)

Now, △ABC is an equilateral triangle .

⇒ AB =  BC = CA

⇒ 1 / 2 AB = 1 / 2 BC = 1 / 2 CA  

⇒ DE = EF = FD [using (i) , (ii) , (iii) ]

Hence, DEF is an equilateral triangle