In the given figure, D is the mid–point of base BC, DE and DF are perpendiculars to AB and AC respectively such that DE=DF. Prove that B= C
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In triangle BDE and triangle CDF,
DE = DF , given
BD= DC , D is the mid point of BC
angle DEB= angle DFC= 90 degree
Therefore BED congruent to CFD by RHS rule
Therefore B=C, cpct
DE = DF , given
BD= DC , D is the mid point of BC
angle DEB= angle DFC= 90 degree
Therefore BED congruent to CFD by RHS rule
Therefore B=C, cpct
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