Question

In the given figure, DA | DC and CB 1 CD. If AQ = BP and DP = CQ, prove
that 2DAQ = ZCBP.

sory i am unable to atach the figure please understand like this only and give full answer with explanation ok

Answer 1

Step-by-step explanation:

$\huge\mathrm{\pink{Answer}}$

Given that , in the figure AD I CD

and CBI CD and AQ = BP , DP = CQ

We have to prove that AngleDAQ = 2CBP

Given that DP = QC

Add PQ on both sides

Given that DP = QC

Add PQ on both sides

→ DP + PQ = PQ + QC

=DQ = PC. ...........( 1 )

Now , consider triangle DAQ and СВР , ,

We have

AngleADQ = AngleBCP = 90 ° [ given]

AQ = BP. .. [ given ]

And DQ = PC [ given ]

So , by RHS congruence criterion , we have ∆DAQ ≅ ∆CBP

Now ,

AngleDAQ = 2CBP 1 : Corresponding parts of congruent triangles are equal ]

.. Hence proved

i hope you like my answer

Answer 2

Answer:

$\huge\mathrm{\purple{+Answer+}}$

Given that, in the figure AD⊥CD and CB⊥CD. AQ = BP and DP = CQ

We have to prove that ∠DAQ=∠CBP

Now, consider triangle DAQ and CBP,

We have

So, by RHS congruence criterion,

we have ΔDAQ≅ΔCBP

Now,

∠DAQ=∠CBP [∵ Corresponding parts of congruent triangles are equal]

∴ Hence proved