In the given figure DE||AC; DF||AE;
BF=4cm; FE=5cm.
Then find BC= ?
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Answer is (C) 7.5 cm AD = 4 cm AE = 5 cm BD = 6 cm In ∆ABC BC || DE ∴ AD/BD = AE/CE (By Basic Prop. Theorem) ⇒ 4/6 = 5/CE ⇒ CE = (6 x 5)/4 ⇒ CE = 7.5 cm
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